Problems of Minimal Resistance and the Kakeya Problem

Detalhes bibliográficos
Autor(a) principal: Plakhov, Alexander
Data de Publicação: 2015
Tipo de documento: Artigo
Idioma: eng
Título da fonte: Repositório Científico de Acesso Aberto de Portugal (Repositórios Cientìficos)
Texto Completo: http://hdl.handle.net/10773/21409
Resumo: Here we solve the problem posed by Comte and Lachand-Robert in [8]. Take a bounded domain R2 and a piecewise smooth nonpositive function u : ¯ ! R vanishing on @ . Consider a flow of point particles falling vertically down and reflected elastically from the graph of u. It is assumed that each particle is reflected no more than once (no multiple reflections are allowed); then the resistance of the graph to the flow is expressed as R(u; ) = 1 | | R (1 + |ru(x)|2)−1dx. We need to find inf ,u R(u; ). One can easily see that |ru(x)| < 1 for all regular x 2 , and therefore one always has R(u; ) > 1/2. We prove that the infimum of R is exactly 1/2. This result is somewhat paradoxical, and the proof is inspired by, and partly similar to, the paradoxical solution given by Besicovitch to the Kakeya problem
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spelling Problems of Minimal Resistance and the Kakeya ProblemNewton’s problem of least resistanceShape optimizationKakeya problemHere we solve the problem posed by Comte and Lachand-Robert in [8]. Take a bounded domain R2 and a piecewise smooth nonpositive function u : ¯ ! R vanishing on @ . Consider a flow of point particles falling vertically down and reflected elastically from the graph of u. It is assumed that each particle is reflected no more than once (no multiple reflections are allowed); then the resistance of the graph to the flow is expressed as R(u; ) = 1 | | R (1 + |ru(x)|2)−1dx. We need to find inf ,u R(u; ). One can easily see that |ru(x)| < 1 for all regular x 2 , and therefore one always has R(u; ) > 1/2. We prove that the infimum of R is exactly 1/2. This result is somewhat paradoxical, and the proof is inspired by, and partly similar to, the paradoxical solution given by Besicovitch to the Kakeya problemSIAM2018-01-10T16:19:08Z2015-08-01T00:00:00Z2015-08info:eu-repo/semantics/publishedVersioninfo:eu-repo/semantics/articleapplication/pdfhttp://hdl.handle.net/10773/21409eng1095-720010.1137/15M1012931Plakhov, Alexanderinfo:eu-repo/semantics/openAccessreponame:Repositório Científico de Acesso Aberto de Portugal (Repositórios Cientìficos)instname:Agência para a Sociedade do Conhecimento (UMIC) - FCT - Sociedade da Informaçãoinstacron:RCAAP2024-05-06T04:11:09Zoai:ria.ua.pt:10773/21409Portal AgregadorONGhttps://www.rcaap.pt/oai/openairemluisa.alvim@gmail.comopendoar:71602024-05-06T04:11:09Repositório Científico de Acesso Aberto de Portugal (Repositórios Cientìficos) - Agência para a Sociedade do Conhecimento (UMIC) - FCT - Sociedade da Informaçãofalse
dc.title.none.fl_str_mv Problems of Minimal Resistance and the Kakeya Problem
title Problems of Minimal Resistance and the Kakeya Problem
spellingShingle Problems of Minimal Resistance and the Kakeya Problem
Plakhov, Alexander
Newton’s problem of least resistance
Shape optimization
Kakeya problem
title_short Problems of Minimal Resistance and the Kakeya Problem
title_full Problems of Minimal Resistance and the Kakeya Problem
title_fullStr Problems of Minimal Resistance and the Kakeya Problem
title_full_unstemmed Problems of Minimal Resistance and the Kakeya Problem
title_sort Problems of Minimal Resistance and the Kakeya Problem
author Plakhov, Alexander
author_facet Plakhov, Alexander
author_role author
dc.contributor.author.fl_str_mv Plakhov, Alexander
dc.subject.por.fl_str_mv Newton’s problem of least resistance
Shape optimization
Kakeya problem
topic Newton’s problem of least resistance
Shape optimization
Kakeya problem
description Here we solve the problem posed by Comte and Lachand-Robert in [8]. Take a bounded domain R2 and a piecewise smooth nonpositive function u : ¯ ! R vanishing on @ . Consider a flow of point particles falling vertically down and reflected elastically from the graph of u. It is assumed that each particle is reflected no more than once (no multiple reflections are allowed); then the resistance of the graph to the flow is expressed as R(u; ) = 1 | | R (1 + |ru(x)|2)−1dx. We need to find inf ,u R(u; ). One can easily see that |ru(x)| < 1 for all regular x 2 , and therefore one always has R(u; ) > 1/2. We prove that the infimum of R is exactly 1/2. This result is somewhat paradoxical, and the proof is inspired by, and partly similar to, the paradoxical solution given by Besicovitch to the Kakeya problem
publishDate 2015
dc.date.none.fl_str_mv 2015-08-01T00:00:00Z
2015-08
2018-01-10T16:19:08Z
dc.type.status.fl_str_mv info:eu-repo/semantics/publishedVersion
dc.type.driver.fl_str_mv info:eu-repo/semantics/article
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status_str publishedVersion
dc.identifier.uri.fl_str_mv http://hdl.handle.net/10773/21409
url http://hdl.handle.net/10773/21409
dc.language.iso.fl_str_mv eng
language eng
dc.relation.none.fl_str_mv 1095-7200
10.1137/15M1012931
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dc.publisher.none.fl_str_mv SIAM
publisher.none.fl_str_mv SIAM
dc.source.none.fl_str_mv reponame:Repositório Científico de Acesso Aberto de Portugal (Repositórios Cientìficos)
instname:Agência para a Sociedade do Conhecimento (UMIC) - FCT - Sociedade da Informação
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instacron_str RCAAP
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reponame_str Repositório Científico de Acesso Aberto de Portugal (Repositórios Cientìficos)
collection Repositório Científico de Acesso Aberto de Portugal (Repositórios Cientìficos)
repository.name.fl_str_mv Repositório Científico de Acesso Aberto de Portugal (Repositórios Cientìficos) - Agência para a Sociedade do Conhecimento (UMIC) - FCT - Sociedade da Informação
repository.mail.fl_str_mv mluisa.alvim@gmail.com
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